CONTENTS
INTRODUCTION
Water is the major constituent of all living beings. Water necessary to sustain all types of life. The water used for drinking purpose by human beings should full the following conditions :
In order to obtain water for drinking purpose, water is first treated with alum whereby clay and other colloidal particles go precipitated the suspended impurities are then removed by filtration and the clear water obtained is subjected to some suitable treatment to destroy harmful germs and bacteria. These bacteria cause many dangerous disease such as cholera, thyroid, dysentery, tuberculosis, diphtheria etc. The process of killing the harmful bacteria by some suitable treatment of water is called STERILIZATION of DISINFECTION OF WATER. The common sterilizer agents are chlorine, ozone, bleaching powder, potassium per magnate chloramines. Sterilization of water through bleaching powder gives chlorine and if it is in excess, it is harmful for health and causes diseases like chlorawis, unconsciousness etc. So here we determine the exact amount of bleaching powder used of required for the sterilization of given samples of water.
General Methods of Sterilizing Water
There are many methods of sterilizing water but the best is one which gives sample of water which is totally free from germs. Sometimes potassium per magnate is used to disinfect water but it is not for drinking as it gives red colour and the excess of it is in harmful for health. We use dissolve in water, so it can not be used in large scale. Another method for disinfection is by simply boiling the water for about 15 minutes, but this powder. The chemical action of bleaching powder on germs and bacteria is due to the chlorine which becomes available, when it is added to water.
So here in the present context, we shall focus on disinfection of water using bleaching powder.
Objective : Our objective of this project is to determine the amount of bleaching powder required for the sterilization of given samples of water. So certain steps are taken in the context as follows :-
1- A known mass of the given samples of bleaching powder is dissolved in water to prepare a solution of known concentration. This solution contains dissolved chlorine, liberated by the action of bleaching powder with water.
CaOCl2 + H2O -------------------> Ca(OH)2 + Cl2
2- The amount of chlorine present in the above solution is determined by treating a known volume of the above solution with excess of 10% potassium iodide solution, when equivalent amount of iodine is liberated. The iodine, thus liberated is then estimated by titrating it against a standard solution of sodium thiosulphate using starch solution as indicator.
Cl2 + 2KI --------------------> 2KCl + I2
I2 + 2Na2S2O3 ------------------> Na2S4O6 + 2NaI
3- A known volume of one of the given samples of water is treated with a known volume of bleaching powder solution. The amount of residual chlorines is determined by adding excess potassium iodine solution and then titrating against standard sodium thio-sulphate solution.
4- From the reading in 2 and 3, the amount of chloring and hence bleaching powder required for the disinfection of a given volume of the given sample of water can be calculated.
Requirements for the Experimental Determination Requirements are as follows :
Apparatus :
Chemicals :
Procedure :
1- Preparation of N/20 Na2SO4 solution :
Take 12.4 gm of sodium thio-sulphate hydrated and mix it in about 500ml of water then the mixture is diluted to make the volume 1000ml. or 1lt.
Normality = strength/Molecular Mass.
= 12.4 / 248 = 1/20N
2- Preparation of 10%KI solution:
Take 25gm. of KI powder and mix it in about 100ml of water then dilute the mixture to make the volume 250 ml and take it in the measuring flask.
3- Preparation of Bleaching Powder solution :
Weight 5gm of bleaching powder and mix it in about 200 ml of distilled water in a conical flask. Stopper the flask and shake it vigorously. The suspension thus obtained is filtered through glass wool in measuring flask of 500ml. and dilute the filtrate with water to make the volume 500 ml. The solution of obtained is 1% bleaching powder of solution.
4- Preparation of starch solution :
Take about 1gm of soluble starch and 10 ml of distilled water in a test table mix vigorously to obtain a paste. Pour the paste in about 100ml. of hot water contained in a beaker with constant stirring. Boil the contents for 4-5min. and then allow to cool.
5- Take 100ml. of distilled of water and then 20ml of bleaching powder of solution in a stopper conical flask and add it 20ml of 10% KI solution. Shake the mixture, titrate this solution against N/20 Na2S2O3
Solution taken in burette. When solution in the conical flask becomes light yellow in colour add about 2ml of starch solution as indicator. The solution now becomes blue in colour. The end point is disappearance of blur colour, so continue titrating till the blue colour just disappears. Repeat the titration to get a set of three readings.
6- Take 100ml of water sample in a conical flask and add 20ml of KI solution and stopper the flask. Shake it and titrates against N/20 Na2S2O3 until the solution become yellow. Then add 2ml of starch solution and then again titrate till the blue colour disappears. Repeat titration for three readings.
7- Repeat the step 6 with other samples of water and records the observation.
Observation Table
Titration : I
Burette Reading
| Sr.No. | Initial | Final | Final Vol. of 0.2N Na2S2O3 sol. used |
| 1. | 1.2ml | 0.9ml | 7.7ml |
| 2. | 0.9ml | 16.6ml | 7.7ml |
| 3. | 16.6ml | 24.0ml | 7.7ml |
Titration : II
Burette Reading
| Sr.No. | Initial | Final | Final Vol. of 0.2N Na2S2O3 sol. used |
| 1. | 10.1 ml. | 16.2 ml. | 6.1 ml. |
| 2. | 16.2 ml. | 22.3 ml. | 6.1 ml. |
| 3. | 22.3 ml. | 28.4 ml. | 6.1 ml. |
Titration : III
Burette Reading
| Sr.No. | Initial | Final | Final Vol. of 0.2N Na2S2O3 sol. used |
| 1. | 8.9 ml. | 14.1 ml. | 5.2 ml. |
| 2. | 14.1 ml. | 19.3 ml. | 5.2 ml. |
| 3. | 19.3 ml. | 14.5 ml. | 5.2 ml. |
Titration : IV
Burette Reading
| Sr.No. | Initial | Final | Final Vol. of 0.2N Na2S2O3 sol. used |
| 1. | 16.1 ml. | 21.6 ml. | 5.5 ml. |
| 2. | 21.1 ml. | 27.1 ml. | 5.5 ml. |
| 3. | 27.1 ml. | 32.6 ml. | 5.5 ml. |
Calculations :
Sample I (TAP WATER)
Amount of bleaching powder used to disinfect 100ml of water samples I.
= (7.7 - 6.1) ml of 0.2 N of Na2S2O3 solution.
= 1.6ml.
1ml of bleaching powder solution contains bleaching powder =5/500 = 0.01gm.
20ml of bleaching powder solution = 7.7ml of 0.2N of Na2SO4
So 1ml of Na2S2O3 solution = 20/7.7 ml of bleaching powder solution.
Volume of bleaching powder solution used to disinfect 100ml of water = 1.6 x 20/7.7ml.
1.6 x 20/7.7 ml. of bleaching powder solution =1.6 x 20 x 0.01 gm / 7.7 = 0.4156 gm
Calculations :
Sample II (POND WATER) :-
Amount of bleaching powder used to disinfect 100ml of water.
= (7.7 - 5.2) ml of 0.2 N Na2S2O3 solution
= 2.5ml
1ml of bleaching powder solution contains bleaching powder = 0.01 gm.
7.7ml. of 0.2N Na2S2O3 = 20ml of bleaching powder solution
So 1ml of Na2S2O3 = 20ml. of bleaching powder solution.
Volume of CaoCl2 solution required to disinfect 100ml of water.
= 2.5 x 20/7.7 ml.
2.5 x 20/7.7 ml. of bleaching powder solution.
= 2.5 x 20 x 0.01 gm / 7.7 of bleaching powder
Amount of bleaching powder required to disinfect 1 let. of water.
= 2.5 x 20 x 0.01 x 1000 / 7.7 x 100 = 25 x 2/7.7 = 0.6493 gm.
Calculations :
Sample III (TANK WATER) :-
Amount of bleaching powder used to disinfect 100ml of water.
= (7.7 - 5.5 ) = 2.2ml of 0.2 N of Na2S2O3 solutions.
1 ml of bleaching powder solution contains bleaching powder.
= 5/500 = 0.01gm
7.7 ml. of 0.2 N Na2S2O3 = 20ml of bleaching powder solution.
so 1ml of 0.2 N Na2S2O3 solution = 20/7.7 ml
volume of bleaching powder solution used to disinfect 100ml of water
= 2.2 x 20/7.7 ml.
2.2 x 20/7.7 ml of bleaching powder solution
= 2.2 x 20 x 0.01 gm / 7.7 of bleaching powder
Amount of bleaching powder used to disinfect 1 ltr. of water
= 2.2 x 20 x 0.01 x 1000 / 7.7 x 100 = 22 x 2/77 = 0.5714gm
Results
Amount of the given samples of bleaching powder required to disinfect one liter of water :-
Samples I = 0.4156
Samples II = 0.6493
Samples III = 0.5714
Thus we get the amount required for disinfection and if bleaching powder is taken less than this amount water will remain impure and if it taken in excess than this will also be harmful as it will contain chlorine.
The results shows that Samples II is the imputes water as the amount of bleaching powder requires is maximum and Sample I is less impure than others as the bleaching powder used is minimum. The tables also show the difference. Titration III has minimum reading because of impurities and titration I has maximum reading because the sample was distilled water.
Conclusion :
This is the convenient method of sterilizing water. It leaves no impurities and its harmful effect if bleaching powder is taken in right amount. In this way we can calculate the amount of bleaching powder required for any sample of water and then take it in large amount if the water is to be disinfected in large scale as in water works.
And thus the only cause of using bleaching powder to disinfect water instead of any other method is this that it kills all germs and bacteria due to its chemical action and provides us a pure sample of water to use for all purpose.